63q^2-52q-20=

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Solution for 63q^2-52q-20= equation:


Simplifying
63q2 + -52q + -20 = 0

Reorder the terms:
-20 + -52q + 63q2 = 0

Solving
-20 + -52q + 63q2 = 0

Solving for variable 'q'.

Factor a trinomial.
(-2 + -7q)(10 + -9q) = 0

Subproblem 1

Set the factor '(-2 + -7q)' equal to zero and attempt to solve: Simplifying -2 + -7q = 0 Solving -2 + -7q = 0 Move all terms containing q to the left, all other terms to the right. Add '2' to each side of the equation. -2 + 2 + -7q = 0 + 2 Combine like terms: -2 + 2 = 0 0 + -7q = 0 + 2 -7q = 0 + 2 Combine like terms: 0 + 2 = 2 -7q = 2 Divide each side by '-7'. q = -0.2857142857 Simplifying q = -0.2857142857

Subproblem 2

Set the factor '(10 + -9q)' equal to zero and attempt to solve: Simplifying 10 + -9q = 0 Solving 10 + -9q = 0 Move all terms containing q to the left, all other terms to the right. Add '-10' to each side of the equation. 10 + -10 + -9q = 0 + -10 Combine like terms: 10 + -10 = 0 0 + -9q = 0 + -10 -9q = 0 + -10 Combine like terms: 0 + -10 = -10 -9q = -10 Divide each side by '-9'. q = 1.111111111 Simplifying q = 1.111111111

Solution

q = {-0.2857142857, 1.111111111}

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